The stability of the nucleus relies on the short range nuclear force. The models produced can account for the nature and energy of radiation products, the results of scattering experiments, and the range of isotopes across the table of elements. We get a measure of stability, the binding energy per nucleon that peaks around iron. Lighter elements will look to fuse together (fusion) and heavier elements to split apart (fission). Makes a source of tremendous amounts of energy.
The natural distance scale for the nucleus is the femtometre (1 fm = \(10^{-15}m\)), the natural energy or mass unit is the mega electron volt (\(1MeV = 1.6 \times 10^{-13}J = 1.78 \times 10^{-30}kg\))
must be something holding nucleus together, stoppping positive protons flying apart
also need to explain radiation
scattering experiments (fire electrons at nucleus and see how they bounce off)
which nuclei are stable
behind all this is the Nuclear Force, the left over remnants of the Strong Force
short range
strongly repulsive at less than 1 fm
sees no difference between neutrons and protons
electrons not affected by it at all
we don’t have a good mathematical model for the nuclear force, a.k.a. QED or QCD
nuclear densities pretty much all the same
surface a little proton rich
shape roughly spherical, a little oblate. Usually.
protons and neutrons moving in orbits within nucleus
energy levels akin to atomic electron energy levels
nuclei with evens numbers of protons and even numbers of neutrons most stable
electrostatic repulsion between protons isn’t nothing
set of magic numbers (a.k.a. noble elements)
Nuclear Valley of Stability (from wikipedia)
looking within a nucleus, we see temporary assemblages of \(\alpha\) particles.
these aren’t static, and collide up against the inner wall of the nucleus frequently
classically they don’t have enough energy to escape, but can get out through quantum mechanical tunnelling
super sensitive to size of barrier, and the energy of this quasi-\(alpha\) particle
Measuring mass in mega-electron volts (MeV)
Makes for a handy unit to measure nuclear energies and masses.
Binding Energy per Nucleon of \(^{238}U\)
\((938.272 \times 92 + 939.565 \times 146 - 221743) / 238 = 7.372\; MeV\; per\; nucleon\)
B/A rises rapidly through the lightest elements
hits a maximum of ~8.75 MeV around \(^{56}Fe\)
decreases gradually beyond that
if we can turn elements into \(^{56}Fe\), from either direction, we can release energy
During Fission, a heavy isotope splits into two or more fragments , this binding energy is released during the process. Nuclear reactors and Atomic bombs make use of this. A typical reaction is \(^1n\; +\; ^{235}U \rightarrow \;^{236}U \rightarrow \;^{141}Ba +\; ^{92}Kr + 3 ^1n\)
Approximately 200 MeV of energy is released per fission
control rods made from Cadmium can be used to absorb neutrons, keep k close to 1
surface to volume ratio important
Fission bomb types
The large numbers of neutrons produced in a reactor can be used to produce nuclear transformations in suitable elements producing radioisotopes for therapy, tracing etc.
absorbtion of neutron is what triggers fission
\(^{235}U\) is even-odd, \(^{236}U\) is even-even
neutron absorbtion is much more probable for slow (thermal, ~10eV) neutrons
natural Uranium is about 1% \(^{235}U\) (mostly \(^{238}U\))
reactor grade is about 20% \(^{235}U\)
weapons grade is about 85% \(^{235}U\)
\(^{239}Pu\) also fissionable
small and modular can be transported by road
higher temperatures so more efficient
liquid salt coolant (Natrium type) can act as energy reservoir
continuous fuel feed so no need to shut down to service
\(^{238}U\) act as neutron absorber to control reaction rates
build on sites of old coal plants
cost about €3B, take ~ 10 years
typically 80-300MW per reactor
use \(^{3}T\) or \(^{2}D\) (tritium or deuterium)
\(^{2}D\) naturally occuring (1 in 6,500 water molecules)
\(^{3}T\) is not, 12 year half-life
need temperatures of about 150 million \(^{\circ} C\)
laser induced fusion (pulse of 2 MJ)
magnetic confinement (20T) in a Tokamak (doughnut shape)
Large science effort, current leaders are Lawrence Livermore in California (laser) and ITER in Cadarache in France (tokomak)
\(1MeV = 1.6 \times 10^{-13}J = 1.78 \times 10^{-30}kg\)
\(Radius\;=\;1.2 \times \sqrt[3]{A}\) in femto-metres (1 fm = \(10^{-15}m\))
\(Binding\; E.\; per\; nucleon = \frac{938.272 \times Z + 939.565 \times (A-Z) - (mass\;in\;MeV)}{A}\)

Physics - Quantum